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What is the space complexity of the following code snippet?
void func(int n) {
if (n <= 0) {
return;
}
cout << n << " ";
func(n - 1);
func(n - 1);
}
func(4);
void func(int n) {
if (n <= 0) {
return;
}
cout << n << " ";
func(n - 1);
func(n - 1);
}
func(4);
- a)O(n)
- b)O(log n)
- c)O(sqrt(n))
- d)O(n log n)
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
What is the space complexity of the following code snippet?void func(i...
Understanding Space Complexity
Space complexity measures the amount of memory required by an algorithm in relation to the input size. In recursive functions, it's essential to consider both the space used by the function's stack frames and any additional data structures.
Analyzing the Function
The provided function `func(int n)` performs the following:
- **Base Case**: It checks if `n` is less than or equal to 0. If so, it returns without further action.
- **Recursive Calls**: If `n` is greater than 0, it prints `n` and then makes two recursive calls to itself with `n - 1`.
Space Complexity Breakdown
- **Recursive Call Stack**: Each time `func` is called, a new stack frame is created. The maximum depth of the recursion is determined by the value of `n`. Therefore, the maximum depth of recursion is `n`, leading to `O(n)` stack space.
- **No Additional Data Structures**: The function does not use any additional data structures that would increase space complexity.
Conclusion
Given that the most significant contributor to space complexity in this scenario is the depth of the recursion (the call stack), the overall space complexity of the function is:
- **Final Space Complexity**: `O(n)`
Thus, the correct answer is **option 'A'**.
Space complexity measures the amount of memory required by an algorithm in relation to the input size. In recursive functions, it's essential to consider both the space used by the function's stack frames and any additional data structures.
Analyzing the Function
The provided function `func(int n)` performs the following:
- **Base Case**: It checks if `n` is less than or equal to 0. If so, it returns without further action.
- **Recursive Calls**: If `n` is greater than 0, it prints `n` and then makes two recursive calls to itself with `n - 1`.
Space Complexity Breakdown
- **Recursive Call Stack**: Each time `func` is called, a new stack frame is created. The maximum depth of the recursion is determined by the value of `n`. Therefore, the maximum depth of recursion is `n`, leading to `O(n)` stack space.
- **No Additional Data Structures**: The function does not use any additional data structures that would increase space complexity.
Conclusion
Given that the most significant contributor to space complexity in this scenario is the depth of the recursion (the call stack), the overall space complexity of the function is:
- **Final Space Complexity**: `O(n)`
Thus, the correct answer is **option 'A'**.
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Community Answer
What is the space complexity of the following code snippet?void func(i...
The function func is recursively called twice for each value of n. The maximum depth of the recursion is n. Therefore, the space complexity is O(n).
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